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2 years ago

7(x+2)+3(x+5)=14(x+1)+2

Mathematics

2 answers:

shtirl [24]2 years ago

8 0

7x + 14 + 3x + 15 = 14x + 14 + 2 10x + 14 = 14x + 16 14 - 16 = 14x - 10x -2 = 4x X = - 2/4 X = - 1/2 OR X = - 0.5

REY [17]2 years ago

8 0

13/4 is the answer to this problem

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lidiya [134]

Sum of roots = - 18

Product of roots = - 8 - 3 =-11

Therefore, y= x^2 + 18x - 11

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2 years ago

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Hitman42 [59]

1)4÷30=7.5 2) 5÷10=2

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2 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

adell [148]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ factoring 96

since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

using exponent rule - $(a^{b}) ^{c} = a^{bc}$

$\sqrt{2^{5} } = 2^{5/2}$

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

doing some simple simplification and $4=2^{2}$ and 6=2*3

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

collecting the roots on one side and applying exponent rule

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$

7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

combining all powers of 2

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

Simplifying

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

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2 years ago

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Using a sheet of graph paper, solve the following system of equations graphically. Be sure to show any work, use a straight edge

Nezavi [6.7K]

Your graph will look like an x (ok, the y axis is at a weird place in my plot). The solution (ie., the point where the two graphs intersect) is at (-1,1).

You can also calculate this by equating the two formulas:

x+y = x-y+2 => 2y = 2 => y=1, x =-1.

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2 years ago

What is the approximate area of a circle enclosed by a piece of rope 50.24 inches long? (Use the fact that π ≈ 3.14 to make your

Nikitich [7]

Answer:

the approximate area of this circle is 200.96 inches long.

Step-by-step explanation:

To answer this problem we need to remember that the area of a circle is given by the formula:

Area = π $r^2$ where r is the radius.

and the perimeter is:

Perimeter = 2πr

Now, the problem tells us that the circle is enclosed by a piece of rope that's 50.24 inches long. So the perimeter of the circle is 50.24 inches.

Since we have the value of the perimeter and the value of pi, we are going to substitute these values in the perimeter formula to find r.

Perimeter = 2πr

50.24=2(3.14)r

50.24= 6.28r

50.24/6.28= r

8= r

Thus, the radius of the circle is 8 inches long.

Now, we can use this value to find the area of the circle:

Area = π $r^2$

Area = π $8^2$

Area = 3.14 (64)

Area = 200.96

Therefore, the approximate area of this circle is 200.96 inches long.

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2 years ago