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max2010maxim [7]
2 years ago
7

How to solve this questions

Mathematics
1 answer:
Lapatulllka [165]2 years ago
6 0

Answerno idea

Step-by-step explanation:

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Please answer the picture
leva [86]

Answer

i dont know the anwser but im trying to do a quest

Step-by-step explanation:

3 0
2 years ago
A man's average speed is 36km/h. How far will he travel in 35 minutes?
JulijaS [17]

Answer:

\huge\boxed{\sf S = 21\ km}

Step-by-step explanation:

<u>Given Data:</u>

Speed = v = 36 km/h

Time = t = 35 mins = 35 / 60 = 0.58 hr

<u>Required:</u>

Distance = S = ?

<u>Formula:</u>

S = v × t

<u>Solution:</u>

S = 36 × 0.58

S = 21 km

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
2 years ago
Read 2 more answers
Given: △ABC, BC&gt;AC, D∈ AC , CD=CB Prove: m∠ABD is acute
nevsk [136]
I want you to imagine as you read this or you can draw through the help of my explanation and see yourself:

1↪Draw triangle ABC where BC>AC

2↪D is any point on AC such that CD=CB

3↪Roughly drawing , you can assume CD=CB and and join BD

4↪SO triangle ABC which is a big triangle is divided into Triangles ABD and BDC

5↪See in triangle BDC ,CD=CB so, base angles of isosceles triangle are equal:
<CDB=<CBD = x (assume) which means x is acute angle since CDB and CBD are are in same triangle with same measure and there can't be any two obtuse angle in any traingle. So x must be acute.

6↪Now see in traingle ABD,

<ADB=180-<CDB=180-x=obtuse angle
...check yourself ...just subtract any acute angle from 180 you will get only obtuse angle (ie angle greater than 90)
That means in triangle ABD , one angle ADB is obtuse which means remaining <ABD and < BAD are acute. [PROVED]

❇Main Concept Used Here:
↪In any triangle there can be maximum of one obtuse angle...so remaining two must be acute angle otherwise interior angles sum can't be equal to 180.
5 0
2 years ago
What is the slope of the line that contains the points (5, –9) and (5, 9)?
Yakvenalex [24]

It would be: (y2-y1) / (x2-x1) = (9-(-9)/5-5 = 18/0 = undefined

OPTION D IS YOUR ANSWER.........

6 0
3 years ago
Read 2 more answers
How to solve #4 and #5
MArishka [77]
If SU bisects TSV, then TSU = USV
4y + 11 = 6y + 5
6y - 4y = 11 - 5 = 6
y = 6/2 = 3

Therefore, m<TSU = 4(3) + 11 = 12 + 11 = 23
7 0
3 years ago
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