The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
35
Step-by-step explanation:
(9 - 3)² - (5 . 4)⁰
= (6)² - (20)⁰
= 36 - 1
= 35
Answer:
Step-by-step explanation:
Plug into distance formula:
Points: (5, -2), (3, -4)
sqrt( ((x2 - x1)^2) + ((y2 - y1)^2))
sqrt( ((3 - 5)^2) + ((-4 + 2)^2))
sqrt( 4 + 4)
sqrt8 ≈ 2.8 OR
sqrt8 = 2√2
You haven't shared all of the possible answers. The graph you've shared has a y-intercept of 4, which differs from the y-intercept of <span>y=−1/2x+8.
Go on to the other 3 possible answers. Which answer shows a y-intercept of 8 and a slope of -1/2?</span>
Team B has a mode of 60, which is the highest mode of all three teams. Team A has a mode of 48 and Team C has a mode of 30. Mode is the number that occurs most frequently in the set of data.
