Check the picture below.
so hmmm let's find the distance AC, which is the only one missing for the perimeter.
![\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2 + b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{AC}\\ a=\stackrel{adjacent}{6}\\ b=\stackrel{opposite}{8}\\ \end{cases} \implies AC=\sqrt{6^2 + 8^2} \\\\\\ AC=\sqrt{100}\implies AC=10~\hfill \underset{Perimeter}{\stackrel{6~~ + ~~8~~ + ~~10}{\text{\LARGE 24}cm}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Busing%20the%20pythagorean%20theorem%7D%20%5C%5C%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20c%3D%5Csqrt%7Ba%5E2%20%2B%20b%5E2%7D%20%5Cqquad%20%5Cbegin%7Bcases%7D%20c%3D%5Cstackrel%7Bhypotenuse%7D%7BAC%7D%5C%5C%20a%3D%5Cstackrel%7Badjacent%7D%7B6%7D%5C%5C%20b%3D%5Cstackrel%7Bopposite%7D%7B8%7D%5C%5C%20%5Cend%7Bcases%7D%20%5Cimplies%20AC%3D%5Csqrt%7B6%5E2%20%2B%208%5E2%7D%20%5C%5C%5C%5C%5C%5C%20AC%3D%5Csqrt%7B100%7D%5Cimplies%20AC%3D10~%5Chfill%20%5Cunderset%7BPerimeter%7D%7B%5Cstackrel%7B6~~%20%2B%20~~8~~%20%2B%20~~10%7D%7B%5Ctext%7B%5CLARGE%2024%7Dcm%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=6\\ h=8 \end{cases}\implies A=\cfrac{1}{2}(6)(8)\implies A=\text{\LARGE 24}~cm^2](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh%20%5Cbegin%7Bcases%7D%20b%3Dbase%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20b%3D6%5C%5C%20h%3D8%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%286%29%288%29%5Cimplies%20A%3D%5Ctext%7B%5CLARGE%2024%7D~cm%5E2)
Answer: 200
Step-by-step explanation:
Number of numbers counted by Alex;
= 2,400 / 6
= 400
Number of numbers counted by Matthew;
= 2,400/4
= 600
Numbers that both of them counted = 600 - 400
= 200
Answer:
y = 4
or (0, 4)
Step-by-step explanation:
intersecting the y-axis is basically when x is equal to 0.
1.5(0) +4.5y = 18
y = 4
So your y-intersect is (0, 4) and thats when it intersects the y-axis.
Answer:
Sum of 4 and 5 → 4 + 5 = 9
Difference of 40 and 4 → 40 – 4 = 36
One-third 1/3 of 36 → 12
→ 12 – 9
» 3
4x + 3 + x - 2 +4x +3 +x - 2
5x + 1 + 4x + 3 + x - 2
5x + 1 + 5x + 1
10x + 2
