DNA is a negatively-charged molecule. Also cell membranes are negatively charged. The problem would be how to push this charges together? I<span>f you put some CaCl2 into the mixture, the CaCl2 will "split" giving 2Cl- and Ca2+. This last ion will be attracted by the negatively charged DNA and will "cover" it, hiding its negative charge. Hope this answers the question.</span>
Answer:
(1) glycerophospholipids ⟶ (C) lipids with phosphate-containing head groups
(2) cerebrosides ⟶ (D) fatty acid linked through an amide bond to the sphingosine C(2)-amine
(3) gangliosides ⟶ (B) anionic sphingolipids containing one or more sialic acid residues
(4) sphingolipids ⟶ (A) built on sphingosine
Explanation:
1) Choline (Fig. 1) is a glycerophospholipid. It is a glycerol-based lipid with a phosphate-containing head group.
(2) Galactosylceramide (Fig. 2) is a cerebroside. It contains a fatty acid linked through an amide bond to the sphingosine C(2)-amine
(3) Gangliosides are glycosphingolipids that contain sialic acid. GQ1b (Fig. 3) is one of the most abundant gangliosides in the human brain. The carboxyl group of the sialic acid is in the ionic form.
(4) Sphingomyelin (Fig. 4) is a sphingolipid. It is based on sphingosine, with a phosphocholine head and a fatty acid chain.
Answer:
Option (e).
Explanation:
Karl Woese was an biophysicist and microbiologist. He was known as the originator of rRNA sequences in 1967.
Karl determines the 16rRNA sequence by the technique pioneered by Woese. He breaks the prokaryotes into two groups and discovered the third domain of life.
Thus, the correct answer is option (e).
A relatively small blood pressure gradient is generally insufficient to move blood through the veins under given conditions, thus venous return must be facilitated by valves within veins and two "pumps." ... As skeletal muscles contract, veins are squeezed to help propel the blood toward the heart.
Answer:
meter
Explanation:
The following equation will be used to solve this question -


Velocity is zero.
Removing out the nullified terms from the above equation, we get -
meter
Hence, top of the liquid in the bottle must be at a height of
meter.