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nexus9112 [7]
3 years ago
15

T m = the number of minutes it will take Beck to finish his homework. Choose the equation that can be used to find the solution

to the problem
Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

0.3 m = 12

Step-by-step explanation:

<em>See comment for complete question</em>

Given

30% in 12 minutes

Required

Time to complete the homework

From the question: m represents the required minutes

This implies that:

30\% * m = 12

Convert to decimal

0.30 * m = 12

0.3 m = 12

Hence:

The equation is: 0.3 m = 12

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Solve for x.<br><br> x+23=−22<br><br> someone help
BaLLatris [955]

Answer:

x = - 45

Step-by-step explanation:

x+23(-23)=−22 (-23)First subtract 23 from both sides

x = - 45

7 0
3 years ago
Evaluate the following expression:<br>p/-3 + (-8)= -8
aalyn [17]
P/-3+(-8)=-8
p/-3-8=-8
Add 8 to each side
p/-3-8+8=-8+8
p/-3=0
Multiply both side by 3
p/-3(3)=0(3)
p=0
Check:
p/-3+(-8)=-8
Substitute p with 0
0/-3+(-8)=-8
0-8=-8
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What is the height of the Tree?<br> 2 m<br> 3 m<br> 30 m
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Answer:

The height of the tree is 3m

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3 years ago
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0
3 years ago
Three-fifths of the 30 days in june are sunny.how many days were sunny?
lara31 [8.8K]
3/5 x 30 days = 18 days were sunny.
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3 years ago
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