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3 years ago

what is the y-intercept of the line perpendicular to the line y = 4/3 x + 1 that includes the point (4, 1)

Mathematics

2 answers:

garik1379 [7]3 years ago

4 0

Answer:

j3rfjjwdjfjahfkjahfkdjfhdkf

Step-by-step explanation: aa a a a a aa a a a a a

Artyom0805 [142]3 years ago

3 0

When solving for a perpendicular line, the slope of a perpendicular line is the negative reciprocal, therefore meaning the slope of the perpendicular line is “y = -3/4x +1”

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4. The students in Mr. Michael’s art class are decorating a booth for Harvest Day. They have blue cloth that is 60 inches long,

MrRissso [65]

Length of blue cloth is 60 inches , length of gold cloth is 48 inches and length of white cloth is 72 inches.

a.

As, the length of all pieces are equal, so for getting the greatest possible length of the pieces, we need to find GCF(greatest common factor) of 60, 48 and 72.

First we will factor out all three numbers completely......

$60=2*2*3*5\\ \\ 48=2*2*2*2*3\\ \\ 72=2*2*2*3*3$

The common factors are: 2, 2 and 3

Thus the GCF $= 2*2*3=12$

So, the greatest possible length of the pieces without having any cloth left over will be 12 inches.

b.

For finding the number of pieces for each color cloth, we will just divide the length of each cloth by 12. So...

Number of pieces for blue cloth $=\frac{60}{12}=5$

Number of pieces for gold cloth $=\frac{48}{12}=4$ and

Number of pieces for white cloth $=\frac{72}{12}=6$

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3 years ago

a box of crayons costs $1.75, including tax. mr. valentino wants to purchase boxes of crayons for his class and has a $25 budget

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4 years ago

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B. Determine the values of a and b so that f is continuous. Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

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3 years ago