I found x by doing cross multiplication. But I’m not sure how to find Y. Can anyone help?

What is the solution of 2m=-6n-5 when n=1,2,3

Travka [436]

Answer:

Step-by-step explanation:

Simplifying

2m + -6n + 5n + 3m = 0

Reorder the terms:

2m + 3m + -6n + 5n = 0

Combine like terms: 2m + 3m = 5m

5m + -6n + 5n = 0

Combine like terms: -6n + 5n = -1n

5m + -1n = 0

Solving

5m + -1n = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add 'n' to each side of the equation.

5m + -1n + n = 0 + n

Combine like terms: -1n + n = 0

5m + 0 = 0 + n

5m = 0 + n

Remove the zero:

5m = n

Divide each side by '5'.

m = 0.2n

Simplifying

m = 0.2n

7 0

2 years ago

Image 1<br>image 2<br>image 3<br>none

Talja [164]

I’d assume image 1 since it’s a combination of multiple substances or a mixture.

7 0

2 years ago

A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 3 feet, 55 feet awa

MariettaO [177]

Answer:

The maximum height of the second pluck is greater than that of the first pluck, hence the second pluck travels further

Also the distance of the maximum height of first pluck from the player is less than the distance of the second pluck from the player hence the second pluck travels further

Step-by-step explanation:

From the question we are told that

The maximum height of the first pluck is $h_1 = 3 \ ft$

The height of the second height is mathematically represented as

$$y=x\left(0.15-0.001x\right)$

=> $y=0.15x -0.001x^2$

Generally at maximum height $y' = 0$

So

$y'=0.15 -0.002 x = 0$

=> $x = 75 \ ft$

Here 75 ft is the horizontal distance the second pluck traveled at maximum height

So the maximum height of the second pluck is mathematically represented as

$y=0.15(75) -0.001(75)^2$

=> $y= 5.625 \ ft$

So comparing the maximum height of the first and the second pluck we see that the maximum height of the second pluck is greater than that of the first pluck, hence the second pluck travels father

3 0

3 years ago

The rectangle below has an area of x2 + 11x + 28 square meters and a length of 2 + 7 meters.

Troyanec [42]

<h3><u>Question:</u></h3>

The rectangle below has an Área of x^2 + 11x + 28 square meters and a length of x+7 meters. What expression represents the width of the rectangle?

<h3><u>Answer:</u></h3>

The expression representing width of rectangle is (x + 4) meters

<h3><u>Solution:</u></h3>

Given that rectangle has an area x^2 + 11x + 28 square meters and a length of x + 7 meters

To find: width of the rectangle

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=\text { length } \times \text { width }$

Here area = x^2 + 11x + 28 square meters

length = x + 7 meters

<em><u>Substituting the values in given formula,</u></em>

$\begin{array}{l}{\text { width }=\frac{x^{2}+11 x+28}{x+7}} \\\\ {\text { width }=\frac{x^{2}+4 x+7 x+28}{x+7}} \\\\ {\text { width }=\frac{x(x+4)+7(x+4)}{x+7}} \\\\ {\text { width }=\frac{(x+4)(x+7)}{x+7}}\end{array}$