For the first Q the answer is the first square on the left 10 miles divided by 12 hours = 0,83 miles
And the second Q goes with the last square 12 hours divided by 10 miles = 1.2 h which in minutes is 72 minutes or 1h and 12 minutes.
Answer:
There are 5 yellow balls
Step-by-step explanation:
40/4 = 10
10/2 = 5
Answer:
To find the area of the rectangular sides, use the formula A = lw
To find the area of the triangular faces, use the formula A = 1/2bh,
Step-by-step explanation:
1st formula where A = area, l = length, and h = height.
2nd formula where A = area, b = base, and h = height.
For this case we have:
The area of the piece of fabric is given by 
Where


Substituting in the formula of the area we have:




Thus, the area of the piece of fabric is given by: 
Answer:

I hope this helps you
✔cos^2A+sin^2A=1
✔1-cos^2A=sin^2A
✔cos2A=cos^2A-sin^2A
✔sin2A=2.sinA.cosA
secA=1/cosA
tgA=sinA/cosA
sin^2A/1/cos^2A-sin^2A/cos^2A
sin^2A.cos^2A/cos2A
2.sin^2A.cos^2A/cos2A
sin2A.2.sin2A/cos2A
tg2A.2.sin2A