Please help....Which fraction has the greatest value?
2 answers:
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Answer:
hello your question has some missing information attached below is the missing information
answer : 112 black balls
Step-by-step explanation:
Given data:
Each bag contains ; 10 balls
Total number of ball = 100 balls
<u>first: calculate the number of Black balls to be picked from the three bags</u>
From bag 1 = 0.4 * 0.35 * 10 = 1.4 balls
From bag 2 = 0.8 * 0.45 * 10 = 3.6 balls
From bag 3 = 0.3 * 0.2 * 10 = 0.6 ball
Total black balls picked = 5.6
∴ percentage of black balls picked given that each bag contains 10
5.6 / 10 * Total balls available = 56 balls = 56% of 100 balls
Hence If the player plays this game 200 times the number of black balls he will pick = 56% * 200 = 112 balls
The volume of the prop is calculated to be 1,875.6 cubic cm.
Step-by-step explanation:
Step 1; The prop consists of a cone and a half-sphere on top. We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.
Step 2; The volume of a cone is determined by multiplying with π, the square of the radius (r²) and height (h). Here we substitute π as 3.14. The radius is 8 cm and the height is 12 cm.
The volume of the cone = × 3.14 × 8 × 8 × 12 = 803.84 cubic cm.
Step 3; The area of a half-sphere is half of a full sphere. The volume of a sphere is given by multiplying with π and the cube of the radius (r³). Here the radius is 8cm. We take π as 3.14.
The volume of a full sphere = × 3.14 × r³ =
× π × 8³ = 2,143.5733 cubic cm.
The volume of a half-sphere = = 1,071.7866 cubic cm.
Step 4; The total volume = The volume of the cone + The volume of the half sphere,
The total volume = 803.84 cubic cm + 1,071.7866 cubic cm = 1,875.6266 cubic cm. By rounding this off to the nearest tenth we get 1,875.6 cubic cm.