I need to find the area below! HELP!
1 answer:
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<u>Answer</u>:
The correct option is C : x² + (y +3)² = 9 .
<u>Step-by-step explanation:</u>
We know that the general equation for a circle is ( x - h )² + ( y -k )²= r², Where,
- r is the radius.
- (h , k) is the center.
Let the point be ( 0 , -y) , since it is on negative y axis . And the circle passes through the origin that is (0,0) . Hence the center will be 3 units down the y - axis that is ( 0 , -3) .Hence h will be 0 and y = (-3) .
Now its given that the radius of the circle is 3. So on substituting r = 3 , in standard form we have ,
⇒ ( x -h )² + ( y - k )²= r²
⇒ ( x - 0)² + { y - (-3) }² = 3²
⇒ x² + ( y + 3) ² = 3²
⇒ x² + ( y + 3)² = 9
<h3><u>Hence the correct option is C [ x² + ( y+3)² = 9 ] .</u></h3>• Note that I have attached the graph of the same .
