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MakcuM [25]
3 years ago
6

I need to find the area below! HELP!

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0
Area of the square: 8x7 = 56
Base of triangle: 3+8+3 = 14
Height of triangle: 12-7 = 5
Area of triangle: 1/2(14)(5) = 35
Area of both: 56 + 35 = 91 in.
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Guys plz help me answer this !!!!
Stella [2.4K]

Answer: -1

Step-by-step explanation:

8-13=s+4s

-5=5s

-5/5=5s/5

-1=s

5 0
3 years ago
Read 2 more answers
May I know this answer
kap26 [50]
I think it’s C but I may be wrong
3 0
3 years ago
Answer these please tell me <br> 1. What the error was<br> 2. How can U check ur answer
emmainna [20.7K]

Answer:

The first one: the error was that the 3 shouldn’t have been moved but the 5 should have. The correct answer is k=-8

The second one: the error was that they added the 6 and 4, you would only get -10 if the 4 was - the correct answer is -2

You can check your answer by plugging in your answer to the variable and making sure both side equal each other

Step-by-step explanation:

The first one: the 5 should be - from both side so you get k=-8

The second one: the 4 should be + to both sides. And the -6 and +4 should be added together to get n=-2

Remember you always want to get the variables by themselves.

Sorry that was a lot. Hope it helps!

8 0
3 years ago
Can you find the missing angle measurements
yarga [219]
Here is the answer for the question

6 0
3 years ago
Read 2 more answers
rectangle ABCD is graphed in the cordinate plane. The following are the verticies of the rectangle; A(-6,-4),B(-4,-4),C(-4,-2),
Sholpan [36]

Answer:

Therefore Perimeter of Rectangle ABCD is 4 units

Step-by-step explanation:

Given:

ABCD is a Rectangle.

A(-6,-4),

B(-4,-4),

C(-4,-2), and

D (-6,-2).

To Find :

Perimeter of Rectangle = ?

Solution:

Perimeter of Rectangle is given as

\textrm{Perimeter of Rectangle}=2(Length+Width)

Length = AB

Width = BC

Now By Distance Formula  we have'

l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting the values we get

l(AB) = \sqrt{((-4-(-6))^{2}+(-4-(-4))^{2} )}

l(AB) = \sqrt{((2)^{2}+(0)^{2} )}=2\ unit

Similarly

l(BC) = \sqrt{((-4-(-4))^{2}+(-2-(-4))^{2} )}

l(BC) = \sqrt{((0)^{2}+(2)^{2} )}=2\ unit

Therefore now

Length = AB = 2 unit

Width = BC = 2 unit

Substituting the values  in Perimeter we get

\textrm{Perimeter of Rectangle}=2(2+2)=2(4)=8\ unit

Therefore Perimeter of Rectangle ABCD is 4 units

8 0
3 years ago
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