Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Answer:
Its the 2nd one
Step-by-step explanation:
Simplify the exponents and then multiply
Answer:
<em>your answer is D lexie will roll an even number roughly 400 times but not exactly 400 times </em>
<em>hope this helps</em>
The percent of his monthly income that will be budgeted for the utilities will be approximately 5.21%.
According to the question,
We have the following information:
Greg evaluated his spending and found that he was spending about $50 more per month on utilities than he has budgeted. He can transfer money from other categories to increase his utilities budget to $125 per month. If his total monthly income is $2,400.
Now, let's take the percent to be x.
We have the following expression:
2400*x/100 = 125
24x = 125
x = 125/24
x = 5.21%
Hence, the percent of his monthly income that will be budgeted for the utilities will be approximately 5.21%.
To know more about percent here
brainly.com/question/28063156
#SPJ4
It would be 2 4/5............i hope this helps you
