Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
60g/12miles = 5g/mile
So, 1200g / 5g = 240 miles
For this case we have the following inequality:
2 ≥ 4 - v
The first thing we must do in this case is to clear the value of v.
We have then:
v ≥ 4 - 2
v ≥ 2
Therefore, the solution set is given by:
[2, inf)
Answer:
See attached image.
ANSWER
C) (6,-8)
EXPLANATION
The equations are:

and

We substitute the first equation into the second equation to get:

We multiply through by 3 to get:

Group similar terms,


Divide both sides by 7 to get,

Put this value of x into the first equation to get;


Answer:
Step-by-step explanation:
∡x = v0t + 1/2 at²
∡x / v0t = 1/2 at²
2∡x / v0t =at²
a = 2∡x / v0t³
that's your answer:)