Vertex is calculated by -b/2a
So we have -(-5)/2(2)=5/4
The root is determined through the quadratic formula:
x=(-b+sqrt(b^2-4ac))/2a
x=(-(-5)+sqrt(-5^2-4(2)(-604)))/2(2)
x=(5+sqrt(25-4832))/4
x=(5+sqrt(-4807))/4
So the root is some imaginary number
Hope this helped!
Answer:
The scale factor from PQR to P'Q'R' is ½
