Answer:
(a)
Step-by-step explanation:
The tangent and the normal at point P are perpendicular.
Given
= 3, then
Given the gradient m of the tangent then the gradient of a line perpendicular to it is
= - 
= - 
→ (a)
The halves of the rhombus separated by line BD are equilateral triangles.
∠BAD = 60°
so
∠ADM is 0.80*60° = 48°.
∠BMD is an exterior angle to ΔAMD, so is equal to the sum
∠BMD = ∠BAD + ∠ADM
= 60° +48° = 108°
∠BMD = 108°
The answer is b. Multiplication from left to right.
Pemdas- exponent, multiplication, division.
Answer:
(7, 0).
Step-by-step explanation:
We have y = 3(x - 7)
y = 3x - 21
Point-slope form is
y - y1 = 3(x - x1)
y - y1 = 3x - 3x1
Comparing this to the equation y = 4x - 21 we see that y1 = 0 and x1 = 7.
