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den301095 [7]
2 years ago
14

The chart below describes the speed of four runners. Which runner is the fastest?

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
6 0

Answer:

Runner B

Step-by-step explanation:

speed = distance ÷ time

Runner A: 1 ÷ 8 = 0.125m/ms

Runner B: 2 ÷ 10 = 0.2m/ms

Runner C: 3 ÷ 20 = 0.15m/ms

Runner D: 5 ÷ 30 = 0.17m/ms

Runner B has the highest speed so he is the fastest runner.

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Use the midpoint formula to find the midpoint between H(3, 9) and J(9, -2).
TiliK225 [7]

Hello!

The midpoint formula is basically an average of x and y.

It is also written as: (\frac{x_{1}+x_{2}} {2},\frac{y_{1}+ y_{2}} {2}).

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(\frac{3 +9}{2}, \frac{9+(-2)}{2}) = (\frac{12}{2}, \frac{7}{2}) = (6, 3.5)

Therefore, the midpoint between points H and J is choice D, (6, 3.5).

3 0
3 years ago
Use the Euclidean Algorithm to find the greatest common divisor of the polynomials f(x) = x^3 + 3x^2 + 6x + 1 and g(x) = 5x^4 +
fomenos

Answer:

3x+1.

Step-by-step explanation:

First we divide g(x)/f(x) (the process is in the first image):

5x-15 in Z7[x] is 5x-1 and 17x^2+86x+16 is r(x)= 3x^2+2x+2 in Z7[x]. So

g(x)/f(x) = (5x-1)(x^3+3x^2+6x+1)+3x^2+2x+2

Now gcd(g,f) = gcm(f,r).

f(x)/r(x) = 5x(3x^2+2x+2) + 3x+1

Then, gcd(f,r) = gcd(r,3x+1).

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Then, gcd(r, 3x+1) = gcd(3x+1,4) = 3x+1.

So, gcd(f,g) = 3x+1.

5 0
3 years ago
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