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Minchanka [31]
3 years ago
10

How many liters of a 10% solution should be mixed with 60 liters of a 25% solution to

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

120 liters of the 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.

Step-by-step explanation:

Let 'x' be the quantity of 10% solution

Given that we need determine many liters of a 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.

As

10% of x = 0.1x

60 liters of a 25%  = 60 × 0.25

Thus,

The equation becomes

0.1x+60\times \:0.25=0.15\left(x+60\right)

Multiply both sides by 100  

0.1x\times \:100+15\times \:100=0.15\left(x+60\right)\times \:100  

10x+1500=15\left(x+60\right)

10x+1500=15x+900

Subtract 1500 from both sides

10x+1500-1500=15x+900-1500

Simplify

10x=15x-600

Subtract 15x from both sides

10x-15x=15x-600-15x

Simplify

-5x=-600

Divide both sides by -5

\frac{-5x}{-5}=\frac{-600}{-5}

Simplify

x=120

Therefore,

  • 120 liters of the 10% solution should be mixed with 60 liters of a 25% solution to  get a 15% solution.                                              
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