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EleoNora [17]
3 years ago
13

AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2​

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
8 0

Answer:

Look at Step by step

Step-by-step explanation:

Mean: (a) 1.38

Mean: (b) 1.7

median (a) 1.3

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Sedbober [7]3 years ago
4 0

Answer:

A)mean is 1.38  mode is 1.5  median is 1.4

B)mean is 1.775  mode is 1.2  median is 1.75

Step-by-step explanation:

the mean is the average of the numbers added together divided by how many numbers are listed. 1.5+1.2+1.3+1.5+1.4=6.9  6.9 divided by 5 = 1.38

mode is the number that shows up in the list the most.

median is the number that is in the middle of the list of numbers when listed highest to lowest or vice versa.

In the instance of (B) since there were only 4 numbers and could not get exact middle number you take the 2 middle numbers and add them together and divide by 2 to get the average of those 2 numbers

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What is the point of intersection of these two lines:<br>25x+10y=100<br>10x+20y=120
wlad13 [49]
Answer:
The point of intersection is (2,5)

Explanation:
To get the point of intersection, we would need to solve the two equations simultaneously. This is because, the point of intersection satisfies both equations.
The first given equation is:
25x + 10y = 100 ..........> equation I
The second given equation is:
10x + 20y = 120
Divide all terms by 10 to simplify, this would given us:
x + 2y = 12
This equation can be rewritten as:
x = 12 - 2y ...........> equation II

Substitute with equation I in equation II and solve for y as follows:
25x + 10y = 100 
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300 - 40y = 100
300 - 100 = 40y
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y = 200 / 40
y = 5
Substitute with y in equation II to get x as follows:
x = 12 - 2y
x = 12 - 2(5)
x = 12 - 10
x = 2

Based on the above, the solution to the system of equations which also represents the point of intersection between the two lines would be (2,5)

Hope this helps :)
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3 years ago
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