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3 years ago

AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

8 0

Answer:

Look at Step by step

Step-by-step explanation:

Mean: (a) 1.38

Mean: (b) 1.7

median (a) 1.3

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Sedbober [7]3 years ago

4 0

Answer:

A)mean is 1.38 mode is 1.5 median is 1.4

B)mean is 1.775 mode is 1.2 median is 1.75

Step-by-step explanation:

the mean is the average of the numbers added together divided by how many numbers are listed. 1.5+1.2+1.3+1.5+1.4=6.9 6.9 divided by 5 = 1.38

mode is the number that shows up in the list the most.

median is the number that is in the middle of the list of numbers when listed highest to lowest or vice versa.

In the instance of (B) since there were only 4 numbers and could not get exact middle number you take the 2 middle numbers and add them together and divide by 2 to get the average of those 2 numbers

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Based on data collected 5 years ago, a hotel expects that 24% of all guests will request smoking rooms. The hotel suspects that

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Answer:

The calculated value Z = 2.3084 > 1.96 at 5% level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

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Step-by-step explanation:

Step(i):-

Given the hotel takes a random sample of 223 guests. Out of this sample, 39 guests requested smoking rooms.

Sample proportion

p = x/n = 39/223 = 0.174

Given Population proportion 'P' = 0.24

Given random sample size 'n' = 223

Level of significance ∝ =0.05

The critical value Z₀.₀₅ = 1.96

Null Hypothesis (H₀) : P=0.24

Alternative Hypothesis (H₁) : P≠ 0.24

Step(ii):-

Test statistic

$Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

$Z = \frac{0.174-0.24}{\sqrt{\frac{0.24 X 0.76}{223} } }$

|Z| = | -2.3084|= 2.3084

The calculated value Z = 2.3084 > 1.96 at 5% level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

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Does anybody know how to do time with exponential decay

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From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

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You can find the amount of original air left in your lungs after $n$ breaths by solving for $b_n$ explicitly. This isn't too hard:

$b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots$

and so on. The pattern is such that you arrive at

$b_n=0.12^{n-1}b_1$

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$b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}$

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AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2​

AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2