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AURORKA [14]
3 years ago
12

X^2-8xy+16y^2 factor completely

Mathematics
2 answers:
kicyunya [14]3 years ago
7 0
Neato
um
requires some trial and error
erm
ah hah

what 2 numbers multiply to get 16 and add to get -8
-4 and -4
(x-4y)(x-4y)
(x-4y)²
olya-2409 [2.1K]3 years ago
6 0
(x-4y)(x-4y)  this is the square of (x-4y)
                                                                   
                                                                              
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The graph below is an be example of which type of function
creativ13 [48]
I don’t see the graph
6 0
3 years ago
I need help with number 8 ASAP
WARRIOR [948]

Answer:

C. 24,429 is the answer

Step-by-step explanation:

formula for volume of a sphere is V=4/3*π*r^3

r=18

r^3=5832

I used 3.14 for pie and just multiplied all that together

hope this helps

comment for more

5 0
2 years ago
Read 2 more answers
Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0
1 year ago
Need some help with this please!!
beks73 [17]

Answer:

B,C and B,A

Step-by-step explanation:

Line the cordients and go up right,Then left to find your answer.

4 0
2 years ago
Ahhh help I have no idea
Monica [59]

Answer:

Solve 3-6x >= 0

6x <= 3

x <= 1/2

Domain: All Real Numbers <= 1/2

7 0
3 years ago
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