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zmey [24]
3 years ago
11

Please help! Geometry is confusing

Mathematics
1 answer:
ddd [48]3 years ago
5 0

Answer:

E is th e answer because that E is upper so since its upper that you would want to add 4x- 8 and then you will get E

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A ladder is leaning against a
vlada-n [284]

Answer:

The angle of elevation is 36.87 degrees

Step-by-step explanation:

see the attached figure to better understand the problem

In the right triangle ABC of the figure

cos(\theta)=\frac{AC}{BC} ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

cos(\theta)=\frac{12}{15}

\theta=cos^{-1}(\frac{12}{15})=36.87^o

4 0
3 years ago
Find the possible values for m<1
Anuta_ua [19.1K]
0.5 that would be half of one if one is greater than the variable M



I really hope this helped ... have a great day !
4 0
2 years ago
Order the following greatest to least <br><br> 1. 10kg<br> 2. 100g<br> 3. 1,000,000mg
svlad2 [7]

Answer:

<em>1, 2, 3</em>

Step-by-step explanation:

Of the three units, the <em>kilogram</em> is the largest and the <em>milligram</em> is the smallest. The prefix “<em>kilo</em>” means a thousand and “<em>milli</em>” means one-thousandths.

1,000,000mg = 1kg  

1kg = 1,000g

8 0
2 years ago
Read 2 more answers
How do you know that 21 over 30 is greater than 2 over 3
Bond [772]
The problem deals with fractions comparison, lets do it:
21/30 > 2/3
we begin solving:
21 > (2/3)*30
21 > 2*10
<span>21 > 20
</span>therefore the proposed inequality is true, <span>21/30 > 2/3

You can solve as well getting same denominator for both fractions and comparing directly, in this case we need to get 2/3 to be divided by 30:
2/3 = (10/10)(2/3) = 20/30
So we have:
</span><span>21/30 > 2/3
</span>which is equal to:
<span>21/30 > 20/30
</span>and we compare directly because both fractions are divided by the same number, and we can see that the inequality is true.
7 0
3 years ago
Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.
gizmo_the_mogwai [7]

Answer:

When y=32, x=16.5

Step-by-step explanation:

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

We are given:

x varies inversely with y

We can write it as: x\:\alpha \:\frac{1}{y}

x=\frac{k}{y}

We have x = 132, when y=4

We can find value of k by using these values

x=\frac{k}{y}\\132=\frac{k}{4}\\k=132*4\\k=528

We need to find x when y=32

x=\frac{k}{y}\\x=\frac{528}{32}\\x=16.5

So, when y=32, x=16.5

6 0
3 years ago
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