-2c+22=10
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The system of equations is -x + y = 4 and -2x + y = 0
<h3>How to create the system of linear equations?</h3>To do this, we make use of the following ordered pairs
(4, 8)
The above point represents April 2008.
Let the system of equations be
mx + ny = 4
2mx + ny = 0
Substitute (4, 8) for x and y in the above equations.
4m + 8n = 4
8m + 8n = 0
Subtract both equations
4m - 8m = 4
This gives
-4m = 4
Divide by 4
m = -1
Substitute m = -1 in 8m + 8n = 0
-8 + 8n = 0
This gives
8n = 8
Divide by 8
n = 1
So, the system of equations is -x + y = 4 and -2x + y = 0
<h3>The graph of the system of equations</h3>The system of equations is -x + y = 4 and -2x + y = 0
See attachment for the graph of the system of equation
<h3>Prove that the solution is (4, 8)</h3>The above is represented in the (a) part of this solution
Verify that the solution is (4, 8)
We have:
-x + y = 4 and -2x + y = 0
Substitute (4, 8) for x and y in the above equations.
-4 + 8 = 4 --- true
-2*4 + 8 = 0 --- true
Both equations are true
Hence, the system of equations have been verified
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