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Effectus [21]
3 years ago
14

Question 1 factor x^2 +8x +15 A. (x+5)(x+3) B. (x+5)(x-3) C. (X-5)(x-3)

Mathematics
1 answer:
Tema [17]3 years ago
3 0
The answer is A (x+5)(x+3)

explanation:
the GCF of 15 is 3 and 5
3 and 5 also add up to 8 making each of the number the zeros

(x+5)(x+3)
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Answer:

C  (–1.16, 1.16)

Step-by-step explanation:

I did the assignment on Edgenuity.

8 0
4 years ago
What is the answer? PLZ HELP
rosijanka [135]
The answer is 40/21.
8 0
3 years ago
Read 2 more answers
15 ‒ 5x = 6x + 3 – 2x
LenKa [72]

Answer:

x = 4/3

Step-by-step explanation:

15 - 5x = 6x + 3 - 2x

In this kind of equation, we try to seperate the x's and the numbers.

So we add 5x to both sides and subtract 3 from both sides to seperate these values

15 - 3 - 5x + 5x = 6x + 3 - 3 - 2x + 5x

=> 12 = 9x

=> 12/9 = x

=> 4/3 = x

=> x = 4/3

To check, we can plug this in.

15 - 5(4/3) = 6(4/3) + 3 - 2(4/3)

15 - 20/3 = 24/3 + 3 - 8/3

45/3 - 20/3 = 24/3 + 9/3 - 8/3

25/3 = 25/3

So our answer works.

7 0
3 years ago
If Sally has 2 apples a Jeremy has 9 apples how did they get 24?
Elza [17]
They bought more apples
6 0
3 years ago
Solve for x:<br><br> -10x/2+x=x+8/x
rosijanka [135]

The\ domain:\\D:\ x\neq-2\ \wedge\ x\neq0\\\\\dfrac{-10x}{2+x}=\dfrac{x+8}{x}\ \ \ \ |\text{cross multiply}\\\\(-10x)(x)=(2+x)(x+8)\\\\-10x^2=(2)(x)+(2)(8)+(x)(x)+(x)(8)\\\\-10x^2=2x+16+x^2+8x\\\\-10x^2=x^2+10x+16\ \ \ +10x^2\\\\11x^2+10x+16=0\\\\a=11,\ b=10,\ c=16\\\\b^2-4ac=10^2-4(11)(16)=100-704=-604 < 0\\\\NO\ REAL\ SOLUTION

3 0
3 years ago
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