Answer:
z=-3 so 2y+3(-3)=-8, 2y-9=-8, add 9 to both sides 2y=1 divide both sides by 2, y=1/2, so 3x+4(1/2)+-3=-2, 3x+2-3=-2, 3x-1=-2, add 1 to both sides, 3x=-1, divide both sides by 3, x=-1/3
A way to add fractions that always works is to multiply each numerator by the denominator of the other, then express the sum of products over the product of the denominators.

Here, you have
The sum is -1 1/12
The drawing shows a circle, with the two lines forming a cross assumed to be perpendicular to each other, so this is most likely to be a square, as the four points at which the perpendicular lines intersect with the circle can be connected to form a square.
We would need 3 points for an equilateral triangle, 5 for a pentagon, and 6 for a hexagon, which do not fit the current steps.
Answer: It has two distinct real zeros.
Step-by-step explanation:
The formula that is used to calculate the discriminant of a Quadratic function is the one shown below:

In this case you have the following Quadractic function provided in the exercise:

Let's make it equal to 0:

You can identify that:

Knowing these values, you can substitute them into the formula and then evaluate:

Therefore, since:

You can determine that the it has two distinct real roots.
Answer:
Increased by a factor of 4
Step-by-step explanation:
The original circumference is:
C1 = 2 * pi * r1
The new circumference is:
C2 = (2 * pi * r2)
"circumference that is 4 times larger than the original"
(2 * pi * r2) = 4 (2 * pi * r1)
Rewriting:
r2 = 4r1
Answer:
The radius of the original circle is:
increased by a factor of 4
Hope this helps :)