Answer:
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Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
It would be the first one (x,-y) because say for example you take the point of v1 (4,-1) and reflect across x axis you get (4,1) for v
Answer:
86+18
Step-by-step explanation:
Use the properties of 45-45-90 triangles to get a side length of 18 for the 2 legs of the isosceles triangle. Then add 43+18, which is the shorter length of the rectangle, +25, which is the longer edge, +18
. The answer is now 86+18
.