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Triss [41]
3 years ago
10

What is true when a reaction reaches equilibrium? Select all that apply. *

Chemistry
1 answer:
Yanka [14]3 years ago
5 0

Answer:

What is true of a reaction that has reached equilibrium? The rate of the forward reaction is greater than the rate of the reverse reaction. The rate of the forward reaction is less than the rate of the reverse reaction. The reaction rates of the forward and reverse reactions are equal. The reaction rate is zero.

Explanation:

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Write a resonance form for pyrrole in which nitrogen has a formal charge of 1. Are comparable resonance forms possible for pyrid
Svetach [21]

Answer:

See explanation and image attached

Explanation:

Here attached are resonance forms of pyrrole and pyridine. The images were obtained from quora and researchgate respectively.

Now, we can see that in the resonance forms of pyrrole, the nitrogen atom in the heterocycle has a formal charge of +1. However, in the six membered pyridine hetrocycle, the nitrogen atom may have a formal charge of -1 or +1 as shown in the canonical structures attached. The structures in which nitrogen has a +1 formal charge in pyridine are comparable to structures obtained from pyrrole. These structures have less contribution to the structure of pyridine.

3 0
3 years ago
How many molecules are in 11 moles of O2? Watch your significant figures. Question 5 options: A. 6.6 atoms of O2 B. 6.62 x 1024
brilliants [131]

Explanation:

6.62 × 1023 atom of O2 is your answer

please mark as brilliant

3 0
3 years ago
URGENT
antoniya [11.8K]

Answer:

a

Explanation:

8 0
3 years ago
PH CHEM, PLEASE HELP QUICK! NO LINKS/VIRUSES PLEASE!
Contact [7]

Answer:

The pH of the solution is 11.48.

Explanation:

The reaction between NaOH and HCl is:

NaOH  +  HCl  →  H₂O  +  NaCl

From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:

n_{NaOH}} = n_{i_{NaOH}} - n_{HCl} = 3.60 \cdot 10^{-3} moles - 5.95 \cdot 10^{-4} moles = 3.01 \cdot 10^{-3} moles

Now, we need to find the concentration of the OH⁻ ions.

[OH^{-}] = \frac{n_{NaOH}}{V}

Where V is the volume of the solution = 1.00 L                

[OH^{-}] = \frac{n_{NaOH}}{V} = \frac{3.01 \cdot 10^{-3} moles}{1.00 L} = 3.01 \cdot 10^{-3} mol/L

Finally, we can calculate the pH of the solution as follows:

pOH = -log([OH^{-}]) = -log(3.01 \cdot 10^{-3}) = 2.52

pH + pOH = 14

pH = 14 - pOH = 14 - 2.52 = 11.48

Therefore, the pH of the solution is 11.48.

I hope it helps you!

3 0
3 years ago
chinua reacts 37g of magnesium with 150g of sulfuric acid. what will be the total mass of the products of this reaction
Andreas93 [3]

the total mass is 187g. The total mass of the reactant is always equal to total mass of the products.

explanation:

as per the given details, the reactant involved in the reaction are 37g of magnesium and 150g of sulfuric acid . the total of the reactant is 187g.

7 0
2 years ago
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