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marta [7]
3 years ago
15

A solution that contains a large amount of salt and a small amount of water is said to be a _______ solution. 

Chemistry
2 answers:
chubhunter [2.5K]3 years ago
7 0
A solution that contains a large amount of salt and a small amount of water is said to be a 
concentrated solution.
The answer is  B. Concentrated 
Hope I helped!
harina [27]3 years ago
3 0
B. concentrated
A. is incorrect because it COULD be saturated. C. is incorrect because a large amount of salt is concentrated into a small amount of water, so it can't be diluted, relatively. D. is incorrect because it does not describe a solution's molality or molarity.
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Nuclear fusion is the source of energy for stars. Besides hydrogen, which other element is most likely also common in stars?
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helium

Explanation:

coz it take part In fusion reaction

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What is the molar mass of nickel (ll) chloride(NiCl2)
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Explanation:

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If you obtain 3.0 grams of aspirin from an experiment that could make no more than 3.14 grams, what is the percent yield?
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96%

Explanation:

To find the percent yield, we can use this equation

\frac{Actual}{Theoretical} *100

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\frac{3.0}{3.14} *100\\\\ =96

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What is the chemical formula for magnesium hydroxide?
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Determine which of the following pairs of reactants will result in a spontaneous reaction at 25°C. None of the above pairs will
Alla [95]

Answer:

Only Fe^{3+}+Mg gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential (E^{0}) of the reaction is positive. Because it leads to negative standard gibbs free energy change (\Delta G^{0}), which is a thermodynamic condition for spontaneity of a reaction.

E^{0}=E^{0}(reduction)-E^{0}(oxidation)

Where E^{0}(reduction) and E^{0}(oxidation) represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         Mg-2e^{-}\rightarrow Mg^{2+} ;  E_{Mg^{2+}\mid Mg}^{0}=-2.38V

Reduction:         Fe^{3+}+3e^{-}\rightarrow Fe ; E_{Fe^{3+}\mid Fe}^{0}=-0.04V

So, E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V

Hence this pair will give spontaneous reaction.

(2) Similarly as above, E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V

Hence this pair will give non-spontaneous reaction.

6 0
3 years ago
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