The mass in kg of the water on the roof after the rainstorm is mathematically given as
The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g or 1.1*10^{7}kg
<h3>What is the mass in kg of the water on the roof after the rainstorm? </h3>
Generally, the equation for the Area of the roof is mathematically given as
height of the rain =5.5cm
the volume of the rain on the roof =1.1 * 10^{10} CC
Generally, the equation for mass is mathematically given as
mass=volume*density
In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10} or $1.1*10^{7}
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Answer: A function can be defined as a relation in which one thing is dependent on another for its value.
Explanation: Given R = 8.314J/mol*k
PV = nRT
V = nRT/ P
V = 8.314RT / P (cm^3)
Volume of gas =(( 8.314 * R* T) / P ) cm3
Answer:
They refer to energy that moves. Kinetic energy is energy that is currently moving. Potential refers to energy that has yet to move, or simply energy in wait
Explanation:
Answer:
1.14 × 10³ mL
Explanation:
Step 1: Given data
- Initial volume of the gas (V₁): 656.0 mL
- Initial pressure of the gas (P₁): 0.884 atm
- Final volume of the gas (V₂): ?
- Final pressure of the gas (P₂): 0.510 atm
Step 2: Calculate the final volume of the gas
If we assume ideal behavior, we can calculate the final volume of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 0.884 atm × 656.0 mL/0.510 atm = 1.14 × 10³ mL
To determine the concentration of the solution of sulfuric acid, the chemist should perform titration with the use of 1.0 M NaOH. This is the answer in the space provided. The 1.0 M NaOH is suitable in the titration because it is a base, which is used in titration in order to determine the unknown concentration.
