Ca=40
C=12
O=16
1 mole of CaCO3 has 100 grams
So 50 grams is 0.5 mole
Answer:
D
Explanation:
This is because, of chemical reaction
Answer:
Usando un purificador que se hace con filtros
Explanation:
Answer:
6,216.684 kilograms of sodium carbonate must be added to neutralize
of sulfuric acid solution.
Explanation:
Mass of sulfuric acid solution = 

Percentage mass of sulfuric acid = 95.0%
Mass of sulfuric acid = 

Moles of sulfuric acid = 

According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.
Then 58,647.96 moles of sulfuric acisd will be neutralized by :
of sodium carbonate
Mass of 58,647.96 moles of sodium carbonate :

6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg
6,216.684 kilograms of sodium carbonate must be added to neutralize
of sulfuric acid solution.