All of the above should be the correct answer
Answer:
100%
Explanation:
This question involves two genes in guinea pigs; one coding for fur color and the other for fur length. The alleles of black fur (B) and short fur (F) is dominant over the alleles for brown fur (b) and long fur (f).
In a cross between two offsprings with genotypes: BBFF x bbff, the following gametes will be produced by each parent:
BBFF - BF, BF, BF, and BF
bbff - bf, bf, bf, bf
Using these gametes in a punnet square (see attached image), one will notice that all of the offsprings will have the genotype: BbFf i.e all or 100% of the offsprings are heterozygous for both of the genes or traits.
Globin 1 and globin 2 genes of insects are understood to have diverged approximately 170 million years ago, through duplication, from a common globin gene ancestor. The two genes that code for haemoglobin have conserved regions; oxygen-binding and heme- regions. Globin 2 gene has lost the intron region that is still present in the globin 1 gene. The percentage divergence is 7.2% with 20 varying nucleotides.
Answer:
1. asexual, mitosis 2. sexual 3. gametes, meiosis 4. haploid 5. sex cells
Explanation:
Asexual reproduction is the form of reproduction that occurs whereby there is no fusion of gametes or a change in the number of chromosomes. The produced daughter cells are genetically similar to the parent. the form of cell division that occurs here is through a process of mitosis.
Different organisms adopt different type of asexual reproduction including binary fission, spore formation, fragmentation etc.
Sexual reproduction in contrast generates genetically unique organism through the fusion of two different organisms sex cells. To accomplish sexual reproduction, gametes that are haploid through a process of meiosis must be produced which are the egg cell and the sperm cells (the sex cells). These haploid cells are produced only in the germ cells to ensure the production of a diploid zygote.
