Find the sum of the first 42 terms of the following series, to the nearest
1 answer:
Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
You might be interested in
Square root (3) < square root (pie) < 2
Answer:
3200/560000983663562666663672
Answer:
43
Step-by-step explanation:
43 is the most the lowest number while the others are around the same range
Hope this helps! Pls mark brainliest!
7x + 4 = 12
7x = 12-4
7x = 8
x = 7/8
Answer:
can u show the screen of the problem i dont understand ^
Step-by-step explanation: