3 years ago

What is Slope and how is it determined from a graph?

1 answer:

5 0

Slope descries both direction and steepness of the line. To determined it from teh graph you must do the rise over run.

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irakobra [83]

8 is the number when triples and then 8 is subtracted to equal 16

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ValentinkaMS [17]

Answer:

i believe it's .0386

Step-by-step explanation:

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ch4aika [34]

I believe C is correct,
Also, did you finish the equation for letter D?

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2 years ago

docker41 [41]

Another expression that is equivalent to 7/2h-3(5h-1/2) is -23/2h+3/2

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2 years ago

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago