Please help me!! Due today

Select all the correct answers.

Nesterboy [21]

Answer:

D. 75(5r+3d+4f) and 75(5r)+75(3d)+75(4f)

5 0

3 years ago

Please help I wanna get an a :(

kramer

Answer:

Graph C

Step-by-step explanation:

Point T is located on Graph C at T(1, 7). To help, (x, y) = count over however many spaces horizontally, then count however many spaces vertically.

It will always be this way.

4 0

3 years ago

Process of development

dezoksy [38]

Answer:

The expression processes of development is used to describe all the processes and mechanisms that contribute to differentiating organizing a living being from the start of life continuing. The result of these processes for any given organism at any given time corresponds to its level of development.

Step-by-step explanation:

the internet. It's pretty great. ;) hope this helps :) have a good day! :D

7 0

3 years ago

(Picture Included) 20 points - can someone solve 11, 12, 13, and 15?

slavikrds [6]

11. 3(5) + 2(4)

15 + 8 = 13

12. x= -12

13. -30

15. x = 44

6 0

4 years ago

mariarad [96]

Answer:

$p_v =P(z>2.087) =0.0184$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.

Step-by-step explanation:

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

$\sigma=2.5$

And the statistic is given by this formula:

$z=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sigma\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}$

Where z follows a normal standard distribution

The system of hypothesis on this case are:

Null hypothesis: $\mu_c \leq \mu_t+1$

Alternative hypothesis: $\mu_c >\mu_t+1$

Or equivalently:

Null hypothesis: $\mu_c - \mu_t \leq 1$

Alternative hypothesis: $\mu_c-\mu_t>1$

Our notation on this case :

$n_c =45$ represent the sample size for group control

$n_t =45$ represent the sample size for group treatment

$\bar X_c =5.2$ represent the sample mean for the group control

$\bar X_t =3.1$ represent the sample mean for the group treatment

And now we can calculate the statistic:

$z=\frac{(5.2-3.1)-(1)}{2.5\sqrt{\frac{1}{45}}+\frac{1}{45}}=2.087$

And now we can calculate the p value using the alternative hypothesis:

$p_v =P(z>2.087) =0.0184$

So with the p value obtained and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the mean for the control group it's not significantly higher than the mean of the treatment group by 1 point.

5 0

3 years ago

Please help me!! Due today​

Please help me!! Due today