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shutvik [7]
2 years ago
10

*PLEASE ANSWER!!!, ILL GIVE BRAINLIEST*

Mathematics
2 answers:
irina1246 [14]2 years ago
6 0

Answer:

C.) Rich lost 20 pounds

Step-by-step explanation:

I hope you have a good rest of your day!

Alexxx [7]2 years ago
5 0

Answer:

Step-by-step explanation:

C

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How can you use the sign of the points to determine location? please help and i will give brainliest :D
Vladimir [108]

To determine the location of a point on a graph, the first number of the ordered pair is a x-coordinate which means the first number you would look for would be the horizontal line, or the x-axis. The second number is the y-coordinate which means that you would look on the vertical line, or the y-axis. You would go on the horizontal line first, then from there go up to the y-coordinate and place your point. (I'm sorry if it's long but you can try to shorten it.)

Hope this helped!

Have a nice day!

8 0
3 years ago
PLEASEE HELP I NEED THIS ASAP!!!!​
Nadusha1986 [10]

Answer:

The second chart has a greater rate of change compared to the equation presented.

Step-by-step explanation:

The first equation has a rate of change of 6. While the chart has a rate of change of 7.

6 0
3 years ago
3-4 litros de jugo de frutilla 1 y 1-2 litros de jugo de manzana 1-8 litro de jugo consentrado de limón . 1 y 1-2 litro de agua.
Neko [114]

Answer:

Hay 3,875 litros de jugo multifrutal.  

Step-by-step explanation:

<em>(Se asume que el problema fue propuesto en un país distinto a los Estados Unidos, razón por la cual se emplea las reglas del Sistema Internacional.)</em>

La capacidad de jugo multifrutal en el bidón se obtiene con la mezcla de cada jugo frutal y se logra mediante la suma de cada capacidad. A partir del enunciado, tenemos que la capacidad del jugo multifrutal es:

V = \frac{3}{4}\,L + 1\,\frac{1}{2}\,L + \frac{1}{8}\,L + 1\,\frac{1}{2}\,L

V = \frac{3}{4}\,L + 1\,L + \frac{1}{2}\,L + \frac{1}{8}\,L + 1\,L + \frac{1}{2}\,L

V = 3,875\,L

Hay 3,875 litros de jugo multifrutal.  

5 0
2 years ago
Rearrange U=1/2KX2 make x the subject
ValentinkaMS [17]

= 1/2kx2

U = potential energy of a spring at a certain position

k = the spring constant, specific to the spring, with units N/m.

x = distance the spring is stretched or compressed away from equilibrium

Potential Energy: Elastic Formula Questions:

1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?

Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:

U = 1/2kx2

U = 1/2(7.50 N/m)(0.40 m)2

U = 0.60 N∙m

U = 0.60 J

4 0
2 years ago
(2x-1)(x+5)(3x-2) expanded and simplified
STatiana [176]
To simplify, we can use the FOIL method. That stands for first, outer, inner, last. What we do is take two factors at a time and multiply the first terms by each other, the outer terms together, etc.

Let's start with (2x-1) and (x+5)

First: 2x * x = 2x^2
Outer: 2x * 5 = 10x
Inner: -1 * x = -x
Last: -1 * 5 = -5

2x^2 + 9x - 5

Now FOIL this result with (3x - 2)

6x^3 - 4x^2 + 27x^2 - 18x - 15x + 10

Simplify:

6x^3 - 23x^2 - 33x + 10





6 0
3 years ago
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