Yogirlnikki sorry i can not see.
If the width is 6.5 then double that to work out the two widths which would be 13. Take that from the perimeter so you're left with 21. Half 21 to work out one length which is 10.5. Length = 10.5
Answer:

Step-by-step explanation:
<u>Factoring</u>
We need to recall the following polynomial identity:

The given expression is:

To factor the above expression, we need to find a and b, knowing a^3 and b^3. a is the cubic root of a^3, and b is the cubic root of b^3:
![a=\sqrt[3]{x^6}=x^2](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7Bx%5E6%7D%3Dx%5E2)
![b=\sqrt[3]{64y^3}=4y](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B3%5D%7B64y%5E3%7D%3D4y)
Now we apply the identity:
![x^6– 64y^3=(x^2-4y)[(x^2)^2+(x^2)*(4y)+(4y)^2]](https://tex.z-dn.net/?f=x%5E6%E2%80%93%2064y%5E3%3D%28x%5E2-4y%29%5B%28x%5E2%29%5E2%2B%28x%5E2%29%2A%284y%29%2B%284y%29%5E2%5D)
Operating:
![x^6– 64y^3=(x^2-4y)[x^4+4x^2y+16y^2]](https://tex.z-dn.net/?f=x%5E6%E2%80%93%2064y%5E3%3D%28x%5E2-4y%29%5Bx%5E4%2B4x%5E2y%2B16y%5E2%5D)
The remaining factors cannot be factored in anymore. Thus the completely factored form is:

Answer:
it is only true if the value of y is 4, any other case, the statement will not be true