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2 years ago

Graph X-intercept of 3 Y-intercept of -8

Mathematics

1 answer:

laiz [17]2 years ago

7 0

Answer:

$\displaystyle 2\frac{2}{3}x - 8$

Step-by-step explanation:

Starting from the y-intercept of $\displaystyle [0, -8],$ you do $\displaystyle \frac{rise}{run}$ by either moving eight blocks south over three blocks west or eight blocks north over three blocks east [west and south are negatives].

I am joyous to assist you anytime.

* 2⅔ = 8⁄3

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Which statement is NOT true about this figure?

Lunna [17]

Answer:

od I'd the correct answer

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2 years ago

What is the diameter of a sphere with a volume of 80487 in", to the nearest tenth of an inch?

hammer [34]

The diameter of a sphere with a volume of 80487, to the NEAREST tenth
is Answer: d=53.57

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2 years ago

Does y = 3/4 x + 6 and y = -3/4 x + 5 have one solution

Mumz [18]

Answer:

yes

Step-by-step explanation:

Given the 2 equations

y = $\frac{3}{4}$ x + 6 → (1)

y = - $\frac{3}{4}$ x + 5 → (2)

Substitute y = $\frac{3}{4}$ x + 6 into (2)

$\frac{3}{4}$ x + 6 = - $\frac{3}{4}$ x + 5 ( add $\frac{3}{4}$ to both sides )

$\frac{3}{2}$ x + 6 = 5 ( subtract 6 from both sides )

$\frac{3}{2}$ x = - 1 ( divide both sides by $\frac{3}{2}$ )

x = $\frac{-1}{\frac{3}{2} }$ = - $\frac{2}{3}$ ← one solution

7 0

2 years ago

Read 2 more answers

Twice the larger of two consecutive integers is equal to sixteen less than three times the smaller find both of the integers

Papessa [141]

Answer:

18 and 19

Step-by-step explanation:

Let the integers be x and x + 1.

=> 2(x + 1) = 3x - 16

=> 2x + 2 = 3x - 16

=> x = 18

=> x + 1 = 19

The integers are :-

18 and 19

4 0

1 year ago

A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of the triangle? Round your answer to the

larisa86 [58]

Use the distance formula to find the length of the sides, then add them up to find the perimeter.

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For points in the form of (x1, y1), (x2, y2).

(-1, 2), (3, 1)

$\sf d=\sqrt{(3+1)^2+(1-2)^2}$

$\sf d=\sqrt{(4)^2+(-1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(3, 1), (7, 2)

$\sf d=\sqrt{(7-3)^2+(2-1)^2}$

$\sf d=\sqrt{(4)^2+(1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(7, 2), (-1, 2)

$\sf d=\sqrt{(-1-7)^2+(2-2)^2}$

$\sf d=\sqrt{(-8)^2+(0)^2}$

$\sf d=\sqrt{64+0}$

$\sf d=\sqrt{64}=8$

So the perimeter will be:

$\sf 8+\sqrt{17}+\sqrt{17}\approx\boxed{\sf 16.25}$

3 0

3 years ago