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solong [7]
3 years ago
5

Hlo sir i am laavanya how are you​

Mathematics
2 answers:
Monica [59]3 years ago
6 0

Answer:

thanks for free point Mark me as brain list

zhuklara [117]3 years ago
4 0

Answer:

Hii follow me

I will follow you back

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How will the solution of the system y > 2x + and y < 2x + change if the inequality sign on both inequalities is reversed t
Gala2k [10]

Answer:

The System of inequality is ,

1. y > 2 x + p

2. y < 2 x + p

Suppose we assign some values to p and q and draw its graph

And, then the inequality sign on both inequalities is reversed

3. y < 2 x + p

4. y > 2 x + p

And , then draw it's graph

it has been found that, the solution set of both the inequality remains same.That is there is no point or set of points , which satisfy both the system of inequality.

The system has no solution.

5 0
3 years ago
Read 2 more answers
Please help me and show your working out thank youu
slava [35]

Answer:

Step-by-step explanation:

mm = 1357

m = 1.357

cm = 135.7

5 0
3 years ago
A pyramid is placed inside a prism as shown. The pyramid has the same base area, B, as the prism but half the height, h, of the
Alona [7]
The general formula of a pyramid with any base is 1/3 bh where b is the area of the base and h is the height. In this case, the height of the pyramid is said to be twice the height of the prism, h. Hence the area becomes 1/3 b*2h or equal to option A. 2/3 bh
4 0
3 years ago
Your teacher is giving you
fomenos
10 4 Points = 40 points
30 2 points = 60 points

10 4 point questions and 30 2 point questions
8 0
3 years ago
The edge length of a cube is changing at a rate of 10 in/sec. At what rate is the cube's volume changing when the edge length is
olya-2409 [2.1K]

Given:

The edge length of a cube is changing at a rate of 10 in/sec.

To find:

The rate by which cube's volume changing when the edge length is 3 inches.

Solution:

We have,

\dfrac{da}{dt}=10\text{ in/sec}

We know that, volume of cube is

V=a^3

Differentiate with respect to t.

\dfrac{dV}{dt}=3a^2\dfrac{da}{dt}

Substituting \dfrac{da}{dt}=10 and a=3, we get

\dfrac{dV}{dt}_{a=3}=3(3)^2(10)

\dfrac{dV}{dt}_{a=3}=3(9)(10)

\dfrac{dV}{dt}_{a=3}=270

Therefore, the volume increased by 270 cubic inches per sec.

7 0
3 years ago
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