Answer:
Solution given
Cos I=adjacent/hypotenuse=16/34
<u>8</u><u>/</u><u>1</u><u>7</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u>.</u>
Answer:
.
Step-by-step explanation:
Answer: £14378
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = £11000
n = 1 because it was compounded once in a year.
For the first 3 years,
r = 3.9% = 3.9/100 = 0.039
Therefore,
A = 11000(1+0.039/1)^1 × 3
A = 11000(1.039)^3
A = $12338
The new principal is 12338
For the next 4 years,
A = 12338(1.039)^4
A = 14378
Answer:
if he uses 1/2 for 2/3, then you can divide 2/3 and 1.2 by 2 to get the remaining soap needed to complete the wash
so to clean the last 1/3 of the car, he`ll use 1/4 of the remaining soap
the entire car needs <u><em>3/4 of a bottle of soap</em></u>
Answer:x=2, y=1, z=-1
Step-by-step explanation:
Given
2x+y+z=4----1
x-y+3z=-2----2
-x+y+z=-2----3
Add 2 & 3 we get
4z=-4
z=-1
Put value of z in 1 & 2
2x+y-1=4
2x+y=5----3
x-y+3(-1)=-2
x-y=1------4
add 3 & 4 we get
x=2
Put x & z in 1
y=1