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Zarrin [17]
3 years ago
12

Solve the simultaneous equations y = 2x^2 y = 3x + 14

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer:

x = -2

And, x = 7 ÷ 2

Step-by-step explanation:

Given that

y = 2x^2

y = 3x + 14

Now equate these two above equations

2x^2 = 3x + 14

2x^2 - 3x - 14

2x^2 -7x + 4x - 14

x(2x - 7) + 2(2x - 7)

(x + 2) (2x - 7)

So it can be x = -2

And, x = 7 ÷ 2

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Answer:

1. x²-2x+15

This can't be factored, I've tried multiple ways now, but it just can't be factored.

2. y²-19y+90​

Let's factor y^2−19y+90

y^2−19y+90

The middle number is -19 and the last number is 90.

Factoring means we want something like

(y+_)(y+_)

Which numbers go in the blanks?

We need two numbers that...

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Can you think of the two numbers?

Try -9 and -10:

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(y-9)(y-10)

Answer:

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