<span>subtract 16 from both sides, you will get
12x= 180
divide by 12
x=15 ft.
Answer: width = 15 ft.; length = 30 ft.
</span>
The net amount they raise is the amount they receive minus what they pay in expenses.
They receive:
$10,000 fixed amount in donations
$55 per person
They pay:
$15 per person
If there are x number of entries, they receive 55x from the entries.
Also, they pay 15x for the entries.
The net amount they raise is amount they receive min us amount they pay:
55x + 10,000 - 15x
which simplifies to
40x + 10,0000
They want to raise at least $55,000.
At least $55,000 means $55,000 or more.
They want to raise an amount greater than or equal to $55,000.
Now we write the inequality:
40x + 10,000 >= 55,000
Now we solve the inequality for x, the number of entries.
40x >= 45,000
x >= 1125
They must have 1125 or more race entries to raise $55,000.
Answer:
0.01 weeks
Step-by-step explanation:
1 min=60sec
1hr=3600sec
1 day = 86400sec
1 week= 604800sec
Therefore answer is 6200/604800= 0.01(approximated)
Answer:
100000(1.04)^t=2[110000(1.04)^t
Step-by-step explanation:
B=2A
100000(1.04)^t=2[110000(1.04)^t
Answer:
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
Step-by-step explanation:
d²y/dx² = (-2y² − x²) / (4y³)
Take the derivative (use quotient rule and chain rule):
d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²
d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)
d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)
d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)
d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)
Substitute:
d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)
d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
