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kari74 [83]
3 years ago
6

What is angle EFG? I need help nowww

Mathematics
2 answers:
krok68 [10]3 years ago
6 0

Answer:

28

Step-by-step explanation:

If <EGF = <EFG, the angles should be the same: 28.

baherus [9]3 years ago
6 0

Answer:

effective field goal range

Step-by-step explanation:

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How do you find absolute extrema for a function?<br> f(x)= (8+x)/(8-x); Interval of [4,6]
Mkey [24]
\bf f(x)=\cfrac{8+x}{8-x}\implies \cfrac{dy}{dx}=\stackrel{quotient~rule}{\cfrac{1(8-x)-(8+x)(-1)}{(8-x)^2}}\implies \cfrac{dy}{dx}=\cfrac{16}{(8-x)^2}

now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.

so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.

therefore, we settle for the endpoints, 4 and 6,

f(4) =3    and      f(6) = 7

doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.
3 0
3 years ago
Mathius walked ⅜ mile to school. Eva walked ⅖ mile to school. How many more
zalisa [80]

Answer:

132ft

Step-by-step explanation:

Mathius Distance = 3/8 mile

Eva Distance        = 2/5 mile

1 mile = 5,280ft

1. Start by multiplying the mile distance of Mathius to the distance of 1 mile in feet.

5,280ft x 3/8 = 15840ft/8 = 1980ft

2. Do the same thing as number 1 but for Eva's distance now.

5,280ft x 2/5 = 10560ft/5 = 2112ft

3. Subtract Eva's Distance from Mathius' Distance for the answer.

2112ft (Eva) - 1980ft (Mathius) = <em>132ft</em>

7 0
3 years ago
The length of a rectangle is represented by (2x2−5x+5)cm and the width is represented by (x2+4x−3)cm. What is the representation
Katarina [22]

Answer: 6x^2-2x+4

Step-by-step explanation:

Given

The length of a rectangle is given by

l=2x^2-5x+5

and the breadth is given by

w=x^2+4x-3

Perimeter is the sum of the sides of rectangle

\therefore \text{Perimeter P= }2(2x^2-5x+5+x^2+4x-3)\\\Rightarrow P=2(3x^2-5x+4x+5-3)\\\Rightarrow P=2(3x^2-x+2)\\\Rightarrow P=6x^2-2x+4

Thus, the perimeter is given by 6x^2-2x+4.

7 0
3 years ago
(a) Find the amount in the account at the end of 1 year.
irina [24]

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5 0
3 years ago
Plese help me! this is worth 25 points dont get it wrong :(
lawyer [7]

Answer:

u forgot to put up a picture :(

8 0
3 years ago
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