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klio [65]
3 years ago
8

During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were record

ed as ABC 30%, CBS 27%, NBC 26%, and independents 17%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 96 homes, CBS 69 homes, NBC 90 homes, and independents 45 homes.Test with α = 0.05 to determine whether the viewing audience proportions changed.State the null and alternative hypotheses.H0: pABC ≠ 0.30, pCBS ≠ 0.27, pNBC ≠ 0.26, pIND ≠ 0.17Ha: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17 H0: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17Ha: pABC ≠ 0.30, pCBS ≠ 0.27, pNBC ≠ 0.26, pIND ≠ 0.17 H0: The proportions are not pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17.Ha: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17 H0: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17Ha: The proportions are not pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17.Find the value of the test statistic. (Round your answer to three decimal places.)Find the p-value. (Round your answer to four decimal places.)p-value =State your conclusion.Reject H0. There has been a significant change in the viewing audience proportions. Reject H0. There has not been a significant
change in the viewing audience proportions. Do not reject H0. There has been a significant change in the viewing audience proportions. Do not reject H0. There has not been a significant change in the viewing audience proportions.
Mathematics
1 answer:
SpyIntel [72]3 years ago
4 0

Part 1: Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

Part 2:

H0:  

Ha:  

Part 3: The test statistic is given as 3.0081.

Part 4: The p-value is given as  0.39037

Step-by-step explanation:

As per the data

Part 2

H0:  

Ha:  

Part 3

As per the sample is of 300 homes, the expected values are given as

ABC=p(ABC)*300=0.30*300=90

CBS=p(CBS)*300=0.27*300=81

NBC=p(NBC)*300=0.26*300=78

IND=p(IND)*300=0.17*300=51

Now the values actually are given as

ABC=94

CBS=71

NBC=88

IND=47

So the test static is given as

So the test statistic is given as 3.0081.

Part 4

Now the degree of freedoms are given as 4-1=3

and chi square  is given as 3.0081 so for α = 0.05 , the p-value is given as  0.39037

Part 1.

As the value of p in part 4 is greater than the value of α = 0.05, thus Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

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the axis of symmetry of a quadratic equation is x = –3. if one of the zeroes of the equation is 4, what is the other zero?
FinnZ [79.3K]
ANSWER

The other zero is

x =  - 10

EXPLANATION

The axis of symmetry serves as the midpoint of the two zeroes.


We were given that the axis of symmetry of the quadratic equation is
x =  - 3


We were also given that, one of the zeroes of the quadratic equation is
x = 4


Let the other zero of the quadratic equation be
x = p

,then, we apply the midpoint formula to find the value of
p

Since it is the x-values of the intercepts that gives the solution, we use only the x-value part of the midpoint formula which is given by,




\frac{x_1 + x_2}{2}  = axis \: of \: symmetry

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We multiply through by 2 to get,

p + 4 =  - 6



This implies that,

p =  - 6 - 4

p =  - 10




3 0
3 years ago
Read 2 more answers
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