Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Its the first one
Plugging in x = -2 and y = -1:-
5(-2) = -10
11(-2) - (9)-1) = -22 + 9 = -13
Answer:
x = ± 
, x = ± i
Step-by-step explanation:
f(x) = 
- x² - 2
to find the zeros , equate f(x) to zero , that is
- x² - 2 = 0
using the substitution u = x² , then
u² - u - 2 = 0 ← in standard form
(u - 2)(u + 1) = 0 ← in factored form
equate each factor to zero and solve for u
u - 2 = 0 ⇒ u = 2
u + 1 = 0 ⇒ u = - 1
convert u back into terms of x
x² = 2 ( take square root of both sides )
x = ±
x² = - 1 ( take square root of both sides )
x = ± 
= ± i
Answer:
The Value of x = 23.1 unit
Step-by-step explanation:
Given:
Parallel line intersect
Find:
The value of "X"
Computation:
We know that given lines are parallels
So, by using Ratio theorem we can find the value of "x"
Ratio theorem of parallel lines say
AB / BC = AD / DE
So,
14 / 20 = x / 33
x = [14 x 33] / 20
The Value of x = 23.1 unit
