Answer:
inequality form: x 
-2 or x > 3
interval notation form: (-∞,-2] ∪ (3,∞)
Step-by-step explanation:
I attached a picture that shows all the work. You begin by isolating then solving for x on both sides. Then form a solution using the information found out about x. For example, you can combine the found inequalities for x to solve that x must be GREATER than 3 while being LESS than -2. Using that you can form an line and make a line. Remember, when writing in interval notation form you always begin from the left to the right (in reference) to the number line.
Answer:
The correct option is;
DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)
Step-by-step explanation:
Given that we have;
1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC
2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC
3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC
Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;
AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))
∴ (sin(m∠ADE)) = (sin(m∠ABC))
m∠ADE) = m∠ABC).
Answer:
y = (1/4)x² - (5/4)x + 1
Step-by-step explanation:
The x-intercepts of the quadratic equation are simply it's roots.
Thus, we have;
(x + 1) = 0 and (x - 4) = 0
Now, formula for quadratic equation is;
y = ax² + bx + c
Where c is the y intercept.
At y-intercept: (0,1), we have;
At (-1,0), thus;
0 = a(1²) + b(1) + 1
a + b = -1 - - - (1)
At (4,0), thus;
0 = a(4²) + b(4) + 1
16a + 4b = -1
Divide both sides by 4 to get;
4a + b = -1/4 - - - (2)
From eq 1, b = -1 - a
Thus;
4a + (-1 - a) = -1/4
4a - 1 - a = -1/4
3a - 1 = -1/4
3a = 1 - 1/4
3a = 3/4
a = 1/4
b = -1 - 1/4
b = -5/4
Thus;
y = (1/4)x² - (5/4)x + 1
Driving with a dog cause you just have to mixed them to ether that’s it
