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3 years ago

1. The perimeter of a rectangular playground is 46 m.

Mathematics

1 answer:

kondor19780726 [428]3 years ago

5 0

Answer: Width= 14 m

Step-by-step explanation: 9+ 9= 18 46-18=28 28/2= 14 m

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3 years ago

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Anuta_ua [19.1K]

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3 years ago

A bag contains 20 slips of paper Individually numbered. If a slip of paper and a letter in the word PENNSYLVANIA is chosen at ra

Soloha48 [4]

Answer:

$P(M4\ n\ V) = 2.083\%$

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

$n(S) = 20$

The outcomes of multiples of 4 is:

$M4= \{4,8,12,16,20\}$

$n(M4) = 5$

So, the probability of multiples of 4 is:

$Pr(M4) = \frac{5}{20}$

$Pr(M4) = \frac{1}{4}$

The sample size of PENNSYLVANIA is:

$n(S) = 12$

The outcome of V is:

$n(V) = 1$

So, the probability of V is:

$P(V) = \frac{1}{12}$

So, the required probability is: P(Multiple of 4 and V)

$P(M4\ n\ V) = P(M4) * P(V)$

$P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}$

$P(M4\ n\ V) = \frac{1}{48}$

$P(M4\ n\ V) = 0.02083$

Express as percentage

$P(M4\ n\ V) = 0.02083 * 100\%$

$P(M4\ n\ V) = 2.083\%$

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3 years ago

5/6÷2/7 in the simplest form

pickupchik [31]

Answer:

2 11/12 mixed number

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help I will give Brainliest please!

WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but $x \ne 0$ </h3>

To write this in interval notation, we can say $(-\infty, 0) \cup (0, \infty)$ which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say $(-\infty, \infty)$ which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation $x = \pm 4$

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer: Oblique asymptote is y = 3x</h3>

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2 years ago