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Juli2301 [7.4K]
3 years ago
15

Can someone plz help me with this one problem plz!!!

Mathematics
2 answers:
katrin [286]3 years ago
7 0

Answer:

no

Step-by-step explanation:

Papessa [141]3 years ago
5 0
No because 13 and 53 are the x,y coordinatinates so 13 = x and 53= y and since it says y=13 it is NOT TRUE
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Jimmy’s Delicatessen sells large tins of Tom Tucker’s Toffee. The deli uses a periodic review system, checking inventory levels
Yakvenalex [24]

Answer:

The restocking level is 113 tins.

Step-by-step explanation:

Let the random variable <em>X</em> represents the restocking level.

The average demand during the reorder period and order lead time (13 days) is, <em>μ</em> = 91 tins.

The standard deviation of demand during this same 13- day period is, <em>σ</em> = 17 tins.

The service level that is desired is, 90%.

Compute the <em>z</em>-value for 90% desired service level as follows:

z_{\alpha}=z_{0.10}=1.282

*Use a <em>z</em>-table for the value.

The expression representing the restocking level is:

X=\mu +z \sigma

Compute the restocking level for a 90% desired service level as follows:

X=\mu +z \sigma

   =91+(1.282\times 17)\\=91+21.794\\=112.794\\\approx 113

Thus, the restocking level is 113 tins.

6 0
4 years ago
Please help me
olganol [36]
Ok so I'm pretty sure you multiply 22.45×5 then multiply 25.45×7 then add your answer
3 0
4 years ago
Plzzz I need help with this question I tried to solve it many times but I can't
blsea [12.9K]

Answer and Step-by-step explanation: Area of a right triangle, (as any other triangle), is calculated as:  A1=\frac{(base)(height)}{2}

Area of a rectangle is calculated as: A2=(side)(side)

Area of a right trapezoid is: A3=\frac{(a+b)h}{2}, where:

a is short base

b is long base

h is height

1) Expressing areas in terms of x:

Area of triangle S1:

S1=\frac{(2x-3)(4x-6)}{2}

S1=4x^{2}-12x+9

Area of rectangle S2:

S2 = (4x-6)(3x-2)

S2=12x^{2}-26x+12

Area of trapezoid S3:

S3=\frac{(2x+3+4x+1)(2x-3)}{2}

S3=\frac{(6x+4)(2x-3)}{2}

S3=6x^{2}-5x-6

2) a) S=4x^{2}-12x+9+12x^{2}-26x+12-(6x^{2}-5x-6)

S=4x^{2}-12x+9+12x^{2}-26x+12-6x^{2}+5x+6

S=10x^{2}-33x+37

Which is the same as S = (2x-3)(5x-9)

b) For the areas to be the same:

\frac{(3x-2+3x-2+2x-3)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}

\frac{(8x-7)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}

32x^{2}-48x-28x+42=12x^{2}+8x-18x-12

20x^{2}-66x+54=0

Using Bhaskara to solve the second degree equation:

\frac{66+\sqrt{(-66)^{2}-(4.20.54)} }{2(20)}

x_{1}=\frac{66+6}{40} = 1.8

x_{2}=\frac{66-6}{40} = 1.5

For the areas of AFGC and ADEB to be equal, x has to be 1.5 or 1.8.

c) <u>Expand</u> <u>a</u> <u>polynomial</u> (or equation) is to multiply all the terms, remiving the parenthesis. <u>Reduce</u> <u>a</u> <u>polynomial</u> (or equation) is to combine terms alike,e.g.:

S=(2x-3)(5x-9)

S=10x^{2}-18x-15x+27 (expand)

S=10x^{2}-33x+27 (reduce)

d) For area of AFCG to be bigger than area of ADEB by 27:

32x^{2}-48x-28x+42=12x^{2}+8x-18x-12+27

32x^{2}-48x-28x+42=12x^{2}+8x-18x+15

20x^{2}-66x+27=0

Solving:

\frac{66+\sqrt{(-66)^{2}-(4.20.27)} }{2(20)}

\frac{66+46.86}{40}

x_{1}=\frac{66+46.86}{40}= 2.82

x_{2}=\frac{66-46.86}{40} = 0.48

According to the enunciation, x cannot be less than 1.5, then, the value of x so that area AFGC exceeds the area ADEB by 27 is 2.82

6 0
3 years ago
Whats 50 times 200 to the fifth power
Svetach [21]

Answer:

1.6e+13

Step-by-step explanation:

50*200^5=1,600,000,000,000

5 0
3 years ago
Read 2 more answers
What is the value of the letter x in this math problem? A. 1620 B. 40 C.360 D.51.4
natka813 [3]

Answer:

B. 40

Step-by-step explanation:

Given:

The given shape is nonagon.

It consist of 9 sides.

We need to find the value of exterior angle 'x'.

Solution:

Now we know that;

"The sum of the exterior angles of any polygon is 360 degrees."

Therefore to find the measure of one exterior angle of any regular (all angles are congruent) polygon, divide 360 by the number of angles.

Since here there is Nonagon then there would be 9 exterior angles.

So measure of angle 'x' = \frac{360}{9} =40\°

Hence The value of 'x'  40°.

7 0
3 years ago
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