<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
A cylinder has a radius of 4 inches and a height of 5 inches. If the radius of the cylinder is tripled and the height remains the same to create a new cylinder, what will be the difference in the surface areas of the two cylinders ? Answer in terms of Pi.
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
A cylinder has a radius of 4 inches and a height of 5 inches.
<h3>To Find:-</h3>
If the radius of the cylinder is tripled and the height remains the same to create a new cylinder, what will be the difference in the surface areas of the two cylinders ?
<h2>Solution:-</h2>
<h3>Let in case of 1st cylinder,</h3>
Radius is 4 inches
Height is 5 inches
<h3>And in case of 2nd cylinder,</h3>
Radius is 3 × 4 = 12 inches [as in the question it is given that the radius of the cylinder is tripled]
Height is 5 inches
Now,
Surface area of 1st cylinder
is 2πr(r + h) = 2π × 4(4 + 5)
= 8π(9)
<h3> = 72π sq inches</h3>
Surface area of 2nd cylinder
is 2πr(r + h) = 2π × 12(12 + 5)
= 24π(17)
<h3> = 408π sq inches</h3>
The difference in the surface areas of the two cylinders is = = (408π - 72π) = 336π sq inches
<h3>The difference in the surface areas of the two cylinders is <u>3</u><u>3</u><u>6</u><u>π</u><u> </u><u>s</u><u>q</u><u> </u><u>i</u><u>n</u><u>c</u><u>h</u><u>e</u><u>s</u>. [Answer]</h3>