Answer:
Step-by-step explanation:
it has no solutions b/c the lines are parallel...but at a different offset.. so they never cross
Answer:
rhombus i think
Step-by-step explanation:
Answer:
its A
Step-by-step explanation:
F is the midpoint of AA' because E.G. bisects AA'.
Answer:
G(6,2)
Step-by-step explanation:
If point 
is the midpoint of the segment GJ, where 
and 
, then
In your case,
therefore,
Thus,
Answer:
B. 45°
Step-by-step explanation:
recall that Thales' theorem states that the diameter of a circle always subtends a right angle on any point on the circle.
what this means is that if ABC is the diameter of the circle, then AD and DC always meet at the circumference at 90°
in this case, if ∠ADC is 90° (by thales theorem), and AD = DC, then we have an isoceles triangle.
This also means that the base angles of the isoceles triangle, ∠DAC and ∠ACD must be equal.
recall that all interior angles of a triangle add up to 180°
180° = ∠ADC + ∠DAC +∠ACD
180° = ∠ADC + 2 ∠ACD
180° = 90° + 2 ∠ACD
2 ∠ACD = 90°
∠ACD = 45°
