Answer:
1) m∠U = 90°
2) m∠C = 80°
Step-by-step explanation:
1) The given figure is a quadrilateral
The sum of the interior angles of quadrilateral = 360°
∴ The sum of the interior angles of the given figure = 360°
Therefore, we have;
80° + 24·x + 4 + 6 + 21·x + 90° = 360°
80° + 45·x + 10 + 90° = 360°
x = (360°- (80° + 10° + 90°))/45 = 4
x = 4
m∠U = 6 + 21·x = 6 + 21 × 4 = 90
m∠U = 90°
2) The sum of the interior angles of the given quadrilateral = 360°
∴ 21·x + 6 + 20·x + 24·x + 4 + 21·x + 6 = 360°
86·x + 16 = 360°
x = (360° - 16°)/86 = 4
x = 4
m∠C = 20·x = 20 × 4 = 80
m∠C = 80°
3) In the figure, some angles are left out, therefore, more information on the remaining angles required
Graph 1 and 3 are the only functions
Answer:
8 red marbles.
Step-by-step explanation:
All together we have 40 marbles. The fraction of marbles that are red is 1/5 which means that we should divide the total number of marbles, which is 40 by the denominator ( Bottom number of fraction ) 5 so that we get the number of groups that have 1 red marble in them. In this case we have 8 groups.
40/5=8
You always divide by the denominator ( Bottom number of fraction ) first and then you multiply your answer by the numerator ( Top number of fraction ) .
If each group has 1 red marble in it and we have 8 groups, it means that we have 8 red marbles in the bag.
1 * 8 = 8 red marbles in the bag
If the numerator (number above the fraction line) was more than one, then this would mean that we have more than 1 marble in each group of marbles.
Example:
If we had 3/5 we would have 3 marbles in each group of marbles. This means that instead of doing 1 * 8 we would have to do 3 * 8 = 24. We would have 24 red marbles in the bag.
Easy and quick way if you do not need the explanation:
Another way we could do this is by simply multiplying the fraction ( 1/5 ) by the total number of marbles ( 40 ). This would still give us an answer of 8 red marbles in the bag. 40/5=8, 8*1=8
Answer:
i). 
ii).
Step-by-step explanation:
Given in the question-
Saving rate is s(t)= 3000(t+2)
We know that savings in the 1st year can be calculated as
![3000\left [ \frac{t^{2}}{2}+2t \right ]_0^1](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7Bt%5E%7B2%7D%7D%7B2%7D%2B2t%20%5Cright%20%5D_0%5E1)
![3000\left [ \frac{1}{2}+2 \right ]](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7B1%7D%7B2%7D%2B2%20%5Cright%20%5D)
=
So savings in the first 5 years can be calculated as
![3000\left [ \frac{t^{2}}{2}+2t \right ]_0^5](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7Bt%5E%7B2%7D%7D%7B2%7D%2B2t%20%5Cright%20%5D_0%5E5)
![3000\left [ \frac{25}{2}+5 \right ]](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7B25%7D%7B2%7D%2B5%20%5Cright%20%5D)
=
