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Jet001 [13]
3 years ago
14

You toss a coin and roll a number cube. Find P(tail and a six).

Mathematics
2 answers:
Dafna11 [192]3 years ago
8 0

There will be 12 possible outcomes. So, the probability of (tail and a sic) would be equal to = 1/12

1/12 is your answer..........

Eduardwww [97]3 years ago
7 0
<span>there are 6 heads and 6 tails as and outcome so
H-T, H-T, H-T, H-T, H-T, H,T
</span>
<span><span>Heads - 1
Heads - 2
Heads - 3
Heads - 4
Heads - 5
Heads - 6
Tails - 1
Tails - 2
Tails - 3
Tails - 4
Tails - 5
Tails - 6
</span>We have to find the probability of tail and 6 so there is only one tail and a  6
</span><span> P(tail and a six) = 1/12</span><span> = 0.08
hope it helps
</span>


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3 years ago
An automobile manufacturer has given its car a 46.7 miles/gallon (MPG) rating. An independent testing firm has been contracted t
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Answer:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

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p_v =2*P(z  

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Step-by-step explanation:

Information given

\bar X=46.5 represent the mean

\sigma=1.1 represent the population standard deviation

n=150 sample size  

\mu_o =46.7 represent the value to verify

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean for this case is 46.7, the system of hypothesis would be:  

Null hypothesis:\mu = 46.7  

Alternative hypothesis:\mu \neq 46.7  

Since we know the population deviation the statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Replacing we got:

z=\frac{46.5-46.7}{\frac{1.1}{\sqrt{150}}}=-2.23    

The p value would be given by:

p_v =2*P(z  

For this case since th p value is lower than the significance level of0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean for this case is significantly different from 46.7 MPG

7 0
3 years ago
Please Help! Look at Screenshot for question.
iogann1982 [59]

Answer:

C

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