2 years ago

I. What is 42% of 18? need help fast!

Mathematics

1 answer:

irina [24]2 years ago

3 0

Answer:

It is 7.56!

Other:

Brainliest? Thanks!

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For a fundraiser , Brad sold 2 less than 3 times the number of candy bars calls that Mary did . If they sold 334 total bars, fin

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$x-\ Mary\\
3x-2-\ Brad\\\\
x+3x-2=334\\
4x-2=334\ \ |add\ 2\\
4x=336\ \ | divide\ by\ 4\\x=84\\
3x-2=3*84-2=252-2=250\\\\
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Which expression is equivalent to (7^3)^-2? (4 points)<br> 1/7^6<br> 7<br> 1/7<br> -1/7^6

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Step-by-step explanation:

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3 years ago

Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow

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Answer:

The answers is " Option B".

Step-by-step explanation:

$CI=\hat{Y}\pm t_{Critical}\times S_{e}$

Where,

$\hat{Y}=$ predicted value of lead content when traffic flow is 15.

$\to df=n-1=8-1=7$

$95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\$

$=\frac{1059.8}{2}\\\\=529.9$

Calculating thet-critical value $t_{ \{\frac{\alpha}{2},\ df \}}=-2.365$

The lower predicted value $=529.9-2.365(Se)$

$463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076$

When $99\%$ of CI use as the expected lead content: $\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)$

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2 years ago

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It seems that you have missed the necessary question for us to answer this problem. Anyway, please complete it first and I will try to get back to you and try to help. Let me know. Have a great day ahead!

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago

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