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jenyasd209 [6]
3 years ago
11

2x^2-5x-10=4x-5 solve algebraically

Mathematics
2 answers:
kkurt [141]3 years ago
4 0

Answer:

by factoring the answer is - x=1/2, 5

Step-by-step explanation:

hope it helps:))

DochEvi [55]3 years ago
3 0

Answer:

x=-½

x=5

Step-by-step explanation:

2x²-5x-10=4x-5

2x²-5x-10-4x+5=0

2x²-9x-5=0

2x²+x-10x-5=0

x(2x+1)-5(2x+1)=0

(2x+1)(x-5)=0

2x+1=0

2x=-1

x=-1/2

x-5=0

x=5

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A water trough is 9 m long and has a cross-section in the shape of an isosceles trapezoid that is 20 cm wide at the bottom, 70 c
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7 0
3 years ago
The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions
Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

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The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}

The quadratic equation can now be solve using factorization method:

\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\  \\ Width=x=5\text{ }ft \end{gathered}

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