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anyanavicka [17]
3 years ago
9

!!)

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0
There’s no circle :/ sorry
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A line segment has an end point of ( -4,-6) which reflection will produce an image with endpoints (-4, 6) and (-6,-4)
HACTEHA [7]
The given point is (-4, -6)

First reflected point is (-4, 6).
Note that the x coordinate is same and y coordinate has opposite sign. Above x-axis, y is positive and below x-axis y is negative. This shows that the reflection was across x-axis which resulted in the change of sign of y coordinate.

Second reflected point is (-6, -4)
Notice that in comparison to the original point, the location of x and y coordinate has been interchanged. This can only happen when the reflection is across the line y = x. The reflection of a graph across y = x also results in the inverse of that graph, with x values and y values interchanging their positions.

So,
1st Answer: Reflection across x-axis
2nd Answer: Reflection across the line y = x
4 0
3 years ago
(4x+3)(3x)-25 graph
maw [93]

Answer:

12x^2+9x^2-25    (quadratic equation)

a=12, b=9, c=-25

put this in quadratic formula

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE HELP <br><br> THERE ARE MANY QUESTIONS LIKE THIS ON MY PAGE SO U CAN JUST KEEP GETTING POINTS
Nastasia [14]

Answer: 1

Step-by-step explanation:

first, i multiplied it all out.

1.5^2/1.5^2

then, i simply divided it all.

1

8 0
3 years ago
What is the value of 9p5?
ICE Princess25 [194]
9.5 is correct (:(:(:
6 0
3 years ago
Tan x + sqrt(3) = - 2 tan x
Svet_ta [14]

9514 1404 393

Answer:

  nπ -π/6 . . . for any integer n

Step-by-step explanation:

  tan(x) +√3 = -2tan(x) . . . . . given

  3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3

  tan(x) = -√3/3 . . . . . . . . . . divide by 3

  x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x

This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...

  x = n·π -π/6 . . . . for any integer n

8 0
2 years ago
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