The given point is (-4, -6)
First reflected point is (-4, 6).
Note that the x coordinate is same and y coordinate has opposite sign. Above x-axis, y is positive and below x-axis y is negative. This shows that the reflection was across x-axis which resulted in the change of sign of y coordinate.
Second reflected point is (-6, -4)
Notice that in comparison to the original point, the location of x and y coordinate has been interchanged. This can only happen when the reflection is across the line y = x. The reflection of a graph across y = x also results in the inverse of that graph, with x values and y values interchanging their positions.
So,
1st Answer: Reflection across x-axis
2nd Answer: Reflection across the line y = x
Answer:
12x^2+9x^2-25 (quadratic equation)
a=12, b=9, c=-25
put this in quadratic formula
Step-by-step explanation:
Answer: 1
Step-by-step explanation:
first, i multiplied it all out.
1.5^2/1.5^2
then, i simply divided it all.
1
9514 1404 393
Answer:
nπ -π/6 . . . for any integer n
Step-by-step explanation:
tan(x) +√3 = -2tan(x) . . . . . given
3tan(x) = -√3 . . . . . . . . . . . add 2tan(x)-√3
tan(x) = -√3/3 . . . . . . . . . . divide by 3
x = arctan(-√3/3) = -π/6 . . . . use the inverse tangent function to find x
This is the value in the range (-π/2, π/2). The tangent function repeats with period π, so the set of values of x that will satisfy this equation is ...
x = n·π -π/6 . . . . for any integer n
